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Given log3(4)≈1.262 and log3(7)≈1.771, what is the value of log3(16/7)?

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log3(16/7) = 1

User Elyse
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Final answer:

The value of log3(16/7) is calculated using the quotient and power rules of logarithms, and with the given values log3(4) and log3(7), it is approximately 0.753.

Step-by-step explanation:

The value of log3(16/7) can be calculated using the properties of logarithms, specifically the quotient rule, which states that the logarithm of a quotient is equal to the difference of the logarithms of the numerator and denominator. The known values given are log3(4) ≈ 1.262 and log3(7) ≈ 1.771.

We can use these values to find log3(16/7) by expressing 16 as 4².

First, we express 16 as 4² and then use the rules of logarithms to write:

log3(16/7) = log3(4²/7)

Now, applying the quotient rule and the power rule of logarithms (loga(b^c) = c * loga(b)), we get:

log3(4²/7) = log3(4²) - log3(7)

log3(4²/7) = 2 * log3(4) - log3(7)

Filling in the given values, we get:

log3(4²/7) = 2 * 1.262 - 1.771

log3(4²/7) = 2.524 - 1.771

= 0.753

Thus, the value of log3(16/7) is approximately 0.753.

User Sascha Doerdelmann
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