Question

What is the value of log2(32)?

Enter your answer in the box.

Answer 1

5

Explanation:

using the rule of logarithms

•
`log_(b)` x = n ⇒ x =
`b^(n)`

given

`log_(2)` (32)

let
`log_(2)` (32) = n , then

32 =
`2^(n)`

note that 32 =
`2^(5)` , then

`2^(5)` =
`2^(n)`

Since the bases on both sides are the same , both 2, then equate the exponents

n = 5

the value of
`log_(2)` (32) = 5