Using the Pythagorean theorem with sides of 5 and 8 units, we found the hypotenuse to be
. Dividing by 2 gives
, or approximately 4.72. Rounding 4.72 to the nearest whole number would be 5.
let’s solve for (x). The image shows a right triangle with sides of 5 and 8 units, and a hypotenuse labeled as (2x). We can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
So, we have:
![[5^2 + 8^2 = (2x)^2 \ 25 + 64 = 4x^2 \ 89 = 4x^2.]](https://img.qammunity.org/2024/formulas/mathematics/high-school/tin18vt6sk3kqvn4n8lo7go0zyajndt3vi.png)
Taking the square root of both sides gives us:
![[x = (√(89))/(2).]](https://img.qammunity.org/2024/formulas/mathematics/high-school/4ow2202z3cw4p5a11bj0jx56g8v4n0s85h.png)
So, (x) equals
, or approximately 4.72 when rounded to two decimal places.