Question

The extremes of the x- ray portion of the electromagnetic spectrum range from approximately 1.0 x 10⁻⁸ m to 1.0 x 10⁻¹³ m.

Find the minimum accelerating voltage required to produce a wavelength of 1.0 x 10⁻⁸ m.

Answer 1

The minimum accelerating voltage required to produce a wavelength of 1.0 x 10^-8 m is 41,287 V.

Step-by-step explanation:

In order to find the minimum accelerating voltage required to produce a wavelength of 1.0 x 10-8 m, we can use the formula:

wavelength = h / (q * V)

Where

wavelength is the desired wavelength (1.0 x 10-8 m)

h is Planck's constant (6.626 x 10-34 J·s)

q is the charge of an electron (1.602 x 10-19 C)

V is the accelerating voltage (unknown)

Substituting the known values, we get:

1.0 x 10-8 = (6.626 x 10-34) / (1.602 x 10-19 * V)

Solving for V:

V = (6.626 x 10-34) / (1.602 x 10-19 * 1.0 x 10-8)

V = 41,287 V

Therefore, the minimum accelerating voltage required to produce a wavelength of 1.0 x 10-8 m is 41,287 V.