Question

Kp for the reaction H2 + I2 = 2HI at 460° C is 49. if the partial pressures of H and I is 0.5 atm respectively,determine the partial pressure of each gas in the equilibrium pressure.

Answer 1

To determine the partial pressures of each gas at equilibrium in the reaction H2 + I2 = 2HI, we can use the equilibrium constant, Kp, and the given partial pressures of H2 and I2. Using the equation Kp = (P(HI))^2 / (P(H2) * P(I2)), we can solve for the partial pressure of HI. In this case, the partial pressure of HI is 3.5 atm.

Step-by-step explanation:

To determine the partial pressures of each gas at equilibrium, we need to use the equilibrium constant, Kp, and the given partial pressures of H2 and I2. Since the reaction is H2 + I2 = 2HI, the equilibrium constant, Kp, is equal to the square of the partial pressure of HI divided by the product of the partial pressures of H2 and I2.

Using the given values, we have Kp = (P(HI))^2 / (P(H2) * P(I2)). Plugging in the values, we can solve for the partial pressure of HI. Given that Kp = 49, P(H2) = 0.5 atm, and P(I2) = 0.5 atm, we can solve the equation to find P(HI).

P(HI) = sqrt(Kp * P(H2) * P(I2)) = sqrt(49 * 0.5 * 0.5) = sqrt(12.25) = 3.5 atm