Final answer:
A convex lens with a focal length of 0.10 m forms a real, inverted image at a position of 4.44 m from the lens. The size of the image is 55.5 times larger than the object.
Step-by-step explanation:
To calculate the position, nature, and size of the image formed by a convex lens, we can use the lens formula and magnification formula.
The lens formula is given by: 1/f = 1/v - 1/u, where f is the focal length, v is the image distance, and u is the object distance.
The magnification formula is given by: magnification (m) = -v/u, where m is the magnification.
Plugging in the given values, we have:
1/0.10 = 1/v - 1/0.08
1/v = 1/0.10 + 1/0.08
1/v = 8/80 + 10/80
1/v = 18/80
v = 80/18 = 4.44 m
The image is formed at a distance of 4.44 m from the lens. Since the image distance is positive, it is a real image formed on the opposite side of the object. The size of the image can be found using the magnification formula:
magnification (m) = -v/u
m = -4.44/0.08
m = -55.5
The negative sign indicates an inverted image. The absolute value of the magnification (|m|) is 55.5.
Therefore, the position of the image is 4.44 m from the lens, the nature of the image is real, inverted, and the size of the image is 55.5 times larger than the object.