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What must the separation be between a 5.2 kg particle and a 2.4 kg particle for their gravitational attraction to have a magnitude of 2.3 1012 n?

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Final answer:

The separation between the two particles must be 1.082 meters for their gravitational attraction to have a magnitude of 2.3 x 10^12 N.

Step-by-step explanation:

The magnitude of the gravitational force between two objects can be calculated using Newton's law of universal gravitation:

F = G * ((m1 * m2) / r^2)

Where F is the magnitude of the gravitational force, G is the gravitational constant (6.674 × 10^-11 N·m²/kg²), m1 and m2 are the masses of the objects, and r is the separation between them.

In this case, we have a particle with a mass of 5.2 kg and another particle with a mass of 2.4 kg. We are given that the magnitude of their gravitational attraction is 2.3 x 10^12 N. We can rearrange the formula to solve for r:

r = sqrt((G * (m1 * m2)) / F)

Plugging in the values, we get:

r = sqrt((6.674 × 10^-11 N·m²/kg² * (5.2 kg * 2.4 kg)) / (2.3 × 10^12 N))

r = 1.082 meters

Therefore, the separation between the two particles must be 1.082 meters for their gravitational attraction to have a magnitude of 2.3 x 10^12 N.

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