Final answer:
To construct the ray diagram for an object in front of a concave mirror, we draw three principal rays: one parallel to the principal axis, one through the focal point, and one through the center of curvature. The intersection of the reflected rays indicates the image's position. Using the mirror equation and magnification formula, we can calculate the image distance and magnification.
Step-by-step explanation:
The question involves constructing a ray diagram for an object placed in front of a concave mirror and determining the characteristics of the image formed. The object is 0.600 cm tall and is placed 16.5 cm to the left of the mirror's vertex, with the mirror having a radius of curvature of 22.0 cm. To draw the ray diagram, we use the following steps:
- Locate the object on the principal axis and mark the principal focus (F) and the center of curvature (C) of the mirror.
- Draw a ray parallel to the principal axis from the top of the object to the mirror; after reflection, it will pass through the focal point.
- Draw a ray passing through the focal point towards the object; upon reflection, it will travel parallel to the principal axis.
- Draw a ray passing through the center of curvature; this ray will reflect back along its own path.
- The intersection point of the reflected rays gives the location of the top of the image.
Using the mirror equation, we can find the image location and magnification. From the given information, since the object distance (do) is 16.5 cm and the radius of curvature (R) is 22.0 cm, the focal length (f) is R/2, which is 11.0 cm. Substituting the values into the mirror equation (1/f = 1/do + 1/di), we can calculate the image distance (di). The magnification (m) is given by -di/do.