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Acceleration of a body is given by the equation a = (4 - 3v) m/s². Speed v is in m/s and t is in second. If initial velocity is zero then terminal velocity of the body is

(a) 8 m/s
(b) m/s
(c) 4 m/s
(d) Infinite

User Harningt
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Final answer:

The terminal velocity of a body, given acceleration a = (4 - 3v) m/s² and an initial velocity of zero, is found to be approximately 1.33 m/s, which does not match any of the provided options.

Step-by-step explanation:

The question is asking for the terminal velocity of a body when acceleration is given by the equation a = (4 - 3v) m/s², with v being the velocity in meters per second (m/s) and t standing for time in seconds. Terminal velocity is reached when the acceleration of the body becomes zero because the resistive forces balance the gravitational force, resulting in no further increase in speed. As per the given acceleration equation, to find the terminal velocity, we need to set acceleration a to zero and solve for v.

Starting with the equation:

0 = (4 - 3v)

Solving for v, we get:

v = 4/3 m/s

Therefore, the terminal velocity of the body is 4/3 m/s, which is approximately 1.33 m/s. This result is not listed among the given options, which indicates a possible issue with the question, as none of the provided choices, (a) 8 m/s, (b) m/s, (c) 4 m/s, (d) Infinite, match our calculated result.

User Zizazorro
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