Question

C(s) + CO₂(g) = 2CO(g)

According to above reaction, partial Pressure of CO₂ & CO are 4 & 8 respectively then find out K, of the above reaction:
(A) 6
(B) 2
(C) 16
(D) 32

Answer 1

The equilibrium constant (K) for the reaction C(s) + CO₂(g) = 2CO(g) is found by using the expression K = (PCO)² / PCO₂ with the given partial pressures of CO (8) and CO₂ (4), resulting in K = 16.

Step-by-step explanation:

To calculate the equilibrium constant (K) for the given reaction C(s) + CO₂(g) = 2CO(g), we need to use the partial pressures of the products and reactants involved in the reaction at equilibrium. The equilibrium constant expression for the reaction in terms of partial pressures is K = (PCO)² / PCO₂.

Given that the partial pressure of CO is 8 and the partial pressure of CO₂ is 4, we substitute these values into the expression to get K = (8²) / 4 which simplifies to K = 64 / 4. Therefore, the equilibrium constant for the reaction is K = 16.