Question

Solve it in cpp if possible

You are given an array A consisting of N positive numbers. You can perform any number of operations, where each operation involves selecting a subarray of the array and replacing it with its sum. Your task is to perform these operations optimally to
make the resultant array non-decreasing.

For example, given the array A: [1, 4, 2, 6, 9], you can choose the subarray A[3, 4] replace it with its sum, resulting in A: [1, 4, 8, 9]. In this case, only one operation and was needed to make the array non-decreasing.

Input Format
The first line contains an integer, where n denotes the number of elements in the array in the array. The second line contains n space-separated integers.
Output Format
Print a number that denotes the maximum length of the non-decreasing array after performing the above operations.
Constraints:
• 3 ≤ n ≤ 10^5
• 1 ≤ arr[I] ≤ 10^5

Answer 1

To solve this problem in C++, you can use a greedy algorithm approach. The task is to make an array non-decreasing using the sum of subarrays in C++.

Step-by-step explanation:

To solve this problem in C++, you can use a greedy algorithm approach. Here's the code:

#include
#include
using namespace std;

int main() {
int n;
cin >> n;
vector arr(n);
for (int i = 0; i < n; i++) {
cin >> arr[i];
}

int ans = 1;
int curr_sum = arr[0];
for (int i = 1; i < n; i++) {
if (arr[i] < curr_sum) {
curr_sum = arr[i];
}
else {
ans++;
curr_sum += arr[i];
}
}

cout << ans << endl;

return 0;
}

This code reads the input array and initializes variables to keep track of the answer and the current sum of the subarray. It then iterates through the array, checking if the current element is greater than or equal to the current sum. If it is, the answer is incremented and the current sum is updated. Finally, the answer is printed.