Final answer:
The units of the constants 'a' and 'b' in the particle's velocity equation v(t) = a + bct², with velocity measured in m/s, are 'a' in meters per second (m/s) and 'b' in seconds (s).
Step-by-step explanation:
The given formula sabudana city appears to have a typographical error and should likely refer to the particle's position or velocity over time, represented by s(t) or v(t).
Given the context of the question, assuming sabudana city to mean v(t) = a + bct², where v(t) represents the velocity of a particle, a and b are constants, c is acceleration, and t is time. Since velocity is given in meters per second (m/s), we can deduce the units for a and b by analyzing the units associated with each term of the equation.
For the constant a, since it is added directly to the rest of the velocity formula, it must have the units of velocity itself, which is meters per second (m/s).
The term ct² has units of acceleration multiplied by time squared. Acceleration is given in meters per second squared (m/s²), and time in seconds (s), so ct² would have units of m/s² × s² or m·s⁻¹. Since b multiplies the ct² term, the units for b will be such that when multiplied by m/s², the resulting units will be m/s. Thus, the units for b are simply seconds (s).