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4 votes
Calculate the e.m.f. (in V) of the cell:

Pt|H₂(g)|BOH(aq)||HA(aq)|H₂(g)|Pt; (0.1 bar;1 M;0.1 M;1 bar
Given: Kₐ (HA)=10⁻⁷, Kb(BOH)=10⁻⁵
A 0.43 V
B 0.36 V
C 0.93 V
D None of these

1 Answer

5 votes

Final answer:

The calculation of the emf of the galvanic cell under the provided conditions requires additional information or formulae to determine the standard reduction potentials for both half-reactions, which are not provided in the question.

option a is the correct

Step-by-step explanation:

The student has asked to calculate the electromotive force (emf) of a galvanic cell with the given conditions: Pt|H2(g)|BOH(aq)||HA(aq)|H2(g)|Pt; (0.1 bar; 1 M; 0.1 M; 1 bar). The provided Ka (HA) is 10-7, and Kb (BOH) is 10-5. To calculate the cell voltage, we first need to determine the standard reduction potentials for both the anode and cathode half-reactions. Then, we will use the Nernst equation to account for the non-standard conditions given (the pressures of hydrogen gas and concentrations of the acid and base).

However, there is not enough information in the provided context to determine the half-reactions and their corresponding standard potentials. Therefore, without additional data or formulae to derive the potentials, I cannot provide an accurate calculation for the emf of the cell.

User Rmic
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