179k views
3 votes
The fraction of a radioactive material which remains active after time t is 9/16. The fraction which remains active after time t/2 will be

A. 4/5
B. 7/8
C. 3/5
D. 3/4

User Ypakala
by
7.7k points

1 Answer

3 votes

Final answer:

To find the fraction of a radioactive material that remains active after time t/2, we can use the equation for radioactive decay. The fraction which remains active after time t/2 is 9/16.

Step-by-step explanation:

To find the fraction of a radioactive material that remains active after time t/2, we can use the equation for radioactive decay. The equation is given by:

N = No * e^(-λt)

where N is the fraction remaining after time t, No is the initial fraction, and λ is the decay constant. Since the fraction remaining after time t is 9/16, we can substitute these values:

9/16 = No * e^(-λt)

Now, we need to find the fraction remaining after time t/2. We can substitute this value in the equation:

N' = No * e^(-λ(t/2))

Simplifying further, we get:

N' = (9/16) * e^(-λ(t/2))

This means that the fraction which remains active after time t/2 is 9/16.

User Michael Angstadt
by
7.9k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories