Final answer:
The stopping potential of a photoelectron can be calculated using the equation for maximum kinetic energy and the charge on the electron. This is done by rearranging the formula to solve for the stopping potential, given the maximum velocity and the specific charge of the electron.
Step-by-step explanation:
To calculate the stopping potential of a photoelectron given its maximum velocity, we can use the equation Kmax = eVs, where e is the charge of the electron, Vs is the stopping potential, and Kmax is the maximum kinetic energy of the photoelectron.
First, we find the maximum kinetic energy (Kmax) of the photoelectron using the equation: Kmax = 0.5 * m * v2, where m is the mass of the electron, and v is the maximum velocity. Using the given maximum velocity, 1.8 × 106 ms−1, and the specific charge of the electron, 1.8 × 1011 Ckg−1, which is e/m, we can rearrange to find e = m * (specific charge).
Once we have the value of e, we can find Vs by simply rearranging the initial equation to Vs = Kmax / e. Substituting the maximum kinetic energy and the charge of the electron into this equation gives us the stopping potential in volts, which can be found by calculating Vs = 0.5 * (1/m * specific charge) * v2. The answer that results from this calculation will match one of the provided options (A, B, C, or D).