The empirical formula of the iron (ii) chloride, given that it contains 0.92 g of iron and 1.18 g of chlorine is
How to calculate the empirical formula for iron (ii) chloride?
The following data were obtained after a careful analysis of the question given:
- Mass of Fe present (Fe) = 0.92 g
- Mass of chlorine present (Cl) = 1.18 g
- Empirical formula =?
The empirical formula can be determined as shown below:
Divide by the smallest
Fe = 0.92 / 55.845 = 0.016
Cl = 1.18 / 35.5 = 0.033
Divide by the smallest
Fe = 0.016 / 0.016 = 1
Cl = 0.033 / 0.016 = 2
Therefore, we can conclude that the empirical formula of the iron (ii) chloride is