Final answer:
2-bromopentane reacts with sodium ethoxide to form 2-pentanol through an SN2 substitution reaction, yielding the alcohol as the highest yield product.option D is correct answer.
Step-by-step explanation:
When 2-bromopentane is treated with CH₃CH₂O- Na+, also known as sodium ethoxide, a substitution reaction takes place. In this reaction, the bromide leaving group is replaced by the ethoxy group from the sodium ethoxide, forming a new compound.
Given the choice between which product is obtained in the highest yield, 2-pentanol (D) would be the expected product. This is due to the nucleophilic substitution mechanism known as SN2, where the nucleophile attacks from the opposite side of the leaving group, leading to the inversion of stereochemistry.
The reaction does not yield significant amounts of alkenes (such as trans or cis pentene) since the conditions are not favorable for elimination reactions but rather for substitution. Therefore, the highest yield is expected for the alcohol, 2-pentanol.