Final answer:
The distance a body covers in the 5th second of its motion with an initial velocity of 7 m/s and uniform acceleration of 24 m/s² is found using the equations of motion for uniformly accelerated motion.
Step-by-step explanation:
The problem is related to kinematics in physics, specifically the equations of motion for uniformly accelerated straight-line motion. To find the distance covered by the body in the 5th second of its motion, we use the equation s = ut + ½at², where s is the displacement, u is the initial velocity, t is the time, and a is the acceleration.
The distance covered in the 5th second can be found by calculating the displacement after 5 seconds and subtracting the displacement after 4 seconds. The equation for this is s = u(t) + ½at² - u(t-1) + ½a(t-1)². With u = 7 m/s, a = 24 m/s², t = 5, and t-1 = 4, we plug these values into the equation to find the distance covered during the 5th second.