Question

Consider two point masses m₁ and m₂ connected by alight rigid rod of length r0. The moment of inertia of the system about an axis passing through their centre of mass and perpendicular to the rigid rod is given by_____

A. m₁m₂/2(m₁+m₂)r₀²
B. m₁m₂/m₁+m₂ r₀²
C. 2m₁m₂/m₁+m₂ r₀²
D. m₁²m₂²/m₁+m₂ r₀²

Answer 1

The moment of inertia of a system consisting of two point masses m₁ and m₂ connected by a light rigid rod of length r₀, about an axis passing through their center of mass and perpendicular to the rod, is given by I = (m₁m₂) / (m₁ + m₂) r₀². The moment of inertia is a measure of an object's resistance to rotational motion. Therefore, the correct answer is A. m₁m₂/2(m₁+m₂)r₀².

Step-by-step explanation:

The moment of inertia of a system consisting of two point masses m₁ and m₂ connected by a light rigid rod of length r₀, about an axis passing through their center of mass and perpendicular to the rod, is given by:

I = (m₁m₂) / (m₁ + m₂) r₀²

where m₁ and m₂ are the masses of the point masses and r₀ is the length of the rigid rod. This formula can be derived using the parallel axis theorem. The moment of inertia is a measure of an object's resistance to rotational motion.

Therefore, the correct answer is A. m₁m₂/2(m₁+m₂)r₀².