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explain the de broglie wavelength. obtain expression for de broglie wavelength of wave associated with material photoelectric work function for a metal is 4.2ev. find the threshold wavelength

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Final answer:

The de Broglie wavelength describes the wave nature of particles in quantum mechanics. The wavelength can be calculated using the equation λ = h / p. To find the de Broglie wavelength associated with the material photoelectric work function, use the equation λ = hc / (E - φ) and substitute the given values.

Step-by-step explanation:

The de Broglie wavelength is a concept in quantum mechanics that describes the wave nature of particles. According to Louis de Broglie's hypothesis, any object with mass and momentum, including particles like electrons, can exhibit wave-like properties. The de Broglie wavelength (λ) of a particle is given by the equation:

λ = h / p


Where:

λ = de Broglie wavelength

h = Planck's constant (6.626 x 10^-34 Js)

p = momentum of the particle



To obtain the expression for the de Broglie wavelength of the wave associated with the material photoelectric work function, we can use the equation:



λ = hc / (E - φ)



Where:



λ = de Broglie wavelength

h = Planck's constant

c = speed of light

E = energy of the photon

φ = work function of the material

In this case, the work function of the metal is given as 4.2 eV. The threshold wavelength, or the maximum wavelength that a photon can have to eject a photoelectron from the metal surface, can be determined by substituting the values into the equation and solving for λ:

λ = (6.626 x 10^-34 Js * 2.998 x 10^8 m/s) / (4.2 eV - 0)

Calculating the above expression gives the value of λ, which is the threshold wavelength.

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