Final answer:
Upon hydrolysis, a compound with the molecular formula C₃H₅N would likely yield a carboxylic acid and ammonia or amine. Assuming the starting material is propanamide, subsequent reaction with N₃H and concentrated H₂SO₄ produces Ethyl amine . option D is correct answer.
Step-by-step explanation:
The question revolves around identifying the product formed when an organic compound with a molecular formula of C₃H₅N undergoes hydrolysis and subsequent reactions with N₃H and concentrated H₂SO₄. The compound with this formula, upon hydrolysis, typically generates an acid and an amine or ammonia. Given that the compound forms an acid upon hydrolysis, it suggests that the starting material may be an amide, as amides hydrolyze to yield carboxylic acids and amines or ammonia.
For example, the hydrolysis of butyramide would yield butyric acid and ammonia. In this case, if we assume the starting compound is a derivative of an amide, like propanamide (propionamide as per Exercise 17.4.1), its hydrolysis would produce propionic acid and ammonia. When ammonia reacts with a nitrous acid derivative (here, NaN₃ is a source of nitrous acid in aqueous solution) and sulfuric acid, it forms an alkyl amine.
Therefore, the resultant product from the reactions is not Propanamide (a) since it is the starting compound in the hydrolysis example. Ethyl acetate (b) is incorrect because it is an ester, not an amine. Methyl amine (c) would have one fewer carbon than our starting amide. The correct answer is D. Ethyl amine, as this is the alkyl amine that would be produced from the given reactions if the starting compound was indeed a propanamide with the given molecular formula.