Final answer:
The question asks about the process type during a gas expansion from volume V to 2V, which could be adiabatic or isothermal. An isothermal expansion at constant temperature allows work calculation as nRTln(2), whereas an adiabatic expansion with no heat exchange results in a temperature drop, not fitting the work formula provided. The problem lacks sufficient data to provide a definitive answer.
Step-by-step explanation:
The question pertains to the sudden expansion of gas and asks to identify the nature of the thermodynamic process involved. When a gas expands suddenly from initial volume V to 2V, several thermodynamic processes could theoretically fit this description, depending on other conditions such as heat exchange and temperature change.
However, the given problem does not provide enough information to conclusively determine the process type (adiabatic, isothermal, etc.) nor the work done. Therefore, without additional context or information specifying whether heat is exchanged or kept constant, or whether the process is carried out slowly or quickly, it is not possible to confidently answer this question.
Typically, an isothermal expansion is characterized by a constant temperature where the system is in thermal equilibrium with a heat reservoir, and work done is given by nRTln(2) for an expansion to twice the volume. In contrast, for a sudden adiabatic expansion, there is no heat exchange with the surroundings, and the temperature of the gas falls; the work done in this case is not given by nRTln(2). Moreover, the entropy typically changes in real processes, though in ideal reversible processes, the total entropy change could be zero.