Question

Write the Lewis Dot Structure for the following atoms or ions.
Al, Cl, K⁺, O²⁻N Si

Answer 1

The Lewis dot structure for a selection of atoms and ions depicts the number of valence electrons as dots around each element's symbol, with aluminum having 3, chlorine 7, potassium ion none (because it has lost one electron), oxygen ion having 8 (due to gaining two electrons), nitrogen 5, and silicon 4.

Step-by-step explanation:

The Lewis dot structure for atoms and ions shows the valence electrons as dots around the symbol of an element. Let's write the Lewis dot structures for the atoms you've asked about:

• Aluminum (Al): Represents 3 valence electrons as dots around the symbol Al.
• Chlorine (Cl): Represents 7 valence electrons as dots around the symbol Cl.
• Potassium ion (K+): Has lost one electron compared to the potassium atom, so no dots are shown around the symbol K.
• Oxygen ion (O2-): Has gained two electrons compared to the oxygen atom, so it has 8 dots in total around the symbol O.
• Nitrogen (N): Represents 5 valence electrons as dots around the symbol N.
• Silicon (Si): Represents 4 valence electrons as dots around the symbol Si.