Question

the integer.parseint method throws a numberformatexception when it is passed a string argument that it cannot convert to an int. assume that a string variable named s has already been declared and assigned a value. also assume that an int variable named i has been declared. write code that uses the integer.parseint method to convert s to an int, and assigns the result to the variable i. if a numberformatexception is thrown, i should be assigned the value -1.

Answer 1

The code provided demonstrates how to convert a string to an integer in Java using Integer.parseInt and how to handle possible NumberFormatException by assigning -1 to the integer variable if the parsing fails.

Step-by-step explanation:

The student is asking how to use the Integer.parseInt method in Java to convert a string to an integer and handle a NumberFormatException. Here's the code that meets these requirements:

try {
i = Integer.parseInt(s);
} catch (NumberFormatException e) {
i = -1;
}

This code attempts to parse the string s into an integer. If the string does not contain a parsable integer, a NumberFormatException is caught and variable i is assigned the value of -1.