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Suppose a certain species of fawns between 1 and 5 months old have a body weight that is approximately normally distributed with mean 30 kilograms and standard deviation ? = 4 kilograms. Let x be the weight of a fawn in kilograms. Convert the following x interval to a z interval. Round to the nearest hundredth.

X < 44.0

A. z < -18.50
B. z > -18.50
C. z < 18.50
D. z < 3.50
E. z > 3.50

1 Answer

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Final answer:

To convert the weight interval x < 44.0 to a z interval, use the formula z = (x - mean) / standard deviation. Plugging in the values, we get z > 3.50.

Step-by-step explanation:

To convert from the weight interval x < 44.0 to a z interval, we need to standardize the weight using the formula z = (x - mean) / standard deviation.

Here, the mean is 30 kg and the standard deviation is 4 kg. Plugging in the values, we get:

z = (44 - 30) / 4 = 3.5.

Rounding to the nearest hundredth, the z interval is z > 3.50.

To convert the weight interval x < 44.0 to a z interval, use the formula z = (x - mean) / standard deviation. Plugging in the values, we get z > 3.50.

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