Question

The sum of 2 numbers is even if either both of them is odd or both of them is even. this means for every pair of consecutive numbers that have the different parity, eliminate one of them. so, to make the adjacent elements sum even, either all elements should be odd or even. so the following greedy algorithm works:

a. go through all the elements in order.
b. count the odd and even elements in the array.
c. return the minimum count.

Answer 1

Option B is answer. The given algorithm is correct for finding the minimum count of either odd or even elements in an array.

Step-by-step explanation:

Yes, the given algorithm is correct for finding the minimum count of either odd or even elements in an array. It works based on the fact that the sum of two numbers is even if either both of them are odd or both of them are even.

Let's say we have an array with elements [1, 2, 3, 4, 5, 6]. If we remove the odd numbers, the array becomes [2, 4, 6], and the sum of these numbers is 12, which is even. Similarly, if we remove the even numbers, the array becomes [1, 3, 5], and the sum of these numbers is 9, which is odd.

Therefore, by counting the odd and even elements in the array and returning the minimum count, we ensure that the adjacent elements will always have an even sum.