Final answer:
The solution involves creating a C program that reads up to 50 integers from a file into an array and counts them. A function called displayGreaterThan is defined to print array elements greater than a specified value, 'n'.
Step-by-step explanation:
The problem is to write a program that reads numbers from a file into an array and keeps track of the count of numbers read. The program should handle different cases depending on whether the file has more than, fewer than, or exactly 50 numbers, taking into consideration the array's size limit. After reading the numbers into the array, a display function is used to show numbers greater than a given value 'n'.
Assume the file is 'numbers.txt' and contains integer values. The program structure in C could be as follows:
#include <stdio.h>
void displayGreaterThan(int array[], int n, int count) {
int i;
for (i = 0; i < count; i++) {
if (array[i] > n) {
printf("%d\\", array[i]);
}
}
}
int main() {
FILE *file = fopen("numbers.txt", "r");
int array[50], count = 0, number;
if (file == NULL) { return -1; }
while (count < 50 && fscanf(file, "%d", &number) == 1) {
array[count++] = number;
}
fclose(file);
int n = 30; // Example threshold value
displayGreaterThan(array, n, count);
return 0;
}
The displayGreaterThan function takes an array, a threshold value 'n', and the count of elements to process. It goes through the array and prints out the values that are greater than 'n'.