Question

Naphthalene, a white solid used to make mothballs, has a vapour pressure of 0.10 mm Hg at 27⁰C.

Kp (in atm) and Kc for the equilibrium are :
C₁₀H₈(s)⇌C₁₀H₈(g)

A. 5×10⁻⁵, 3.4×10⁻²
B. 3.4×10⁻²,5×10⁻⁵
C. 1.32×10⁻⁴,5.34×10⁻⁶
D. 5.34×10⁻⁶,1.82×10⁻⁴

Answer 1

The equilibrium constant Kp is equal to Kc for the given reaction.

option d is the correct

Step-by-step explanation:

The equilibrium constant Kc for the reaction C₁₀H₈(s) ⇌ C₁₀H₈(g) at a given temperature can be related to the Kp value, which represents the equilibrium constant in terms of partial pressures. The relationship is given by the equation Kc = Kp(RT)^(∆n), where R is the ideal gas constant, T is the temperature in Kelvin, and ∆n is the difference in the number of moles of gaseous products and reactants. In this case, the number of moles of gaseous reactants and products is the same, so ∆n = 0.

Since ∆n = 0, the equation becomes Kc = Kp(RT)^0 = Kp. Therefore, Kp is equal to Kc for this particular equilibrium.

Given that the Kc for the equilibrium is 5.34×10⁻⁶ atm, the answer is option D: 5.34×10⁻⁶,1.82×10⁻⁴.