Final answer:
The reaction between acetyl bromide and CH₃MgI followed by hydrolysis with NH₄Cl forms acetone through a Grignard reaction. This is due to the nucleophilic addition of the Grignard reagent to the carbonyl group. The correct answer is A. Acetone.
Step-by-step explanation:
The question involves a chemical reaction where acetyl bromide reacts with excess methylmagnesium iodide (CH₃MgI), followed by hydrolysis with a saturated solution of ammonium chloride (NH₄Cl). This type of reaction is known as a Grignard reaction, which typically forms an alcohol. However, in this case, the reaction proceeds to form a ketone, rather than an alcohol, due to the presence of a carbonyl group in acetyl bromide.
The Grignard reagent adds to the carbonyl carbon, followed by protonation during the hydrolysis step, which leads to the formation of acetone (option A). Acetamide, 2-methyl-2-propanol, and acetyl iodide are not the correct answers as they would result from different starting materials or reaction conditions. Therefore, when choosing any one option in the final part clearly, the correct option in the final answer is A. Acetone.