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The density of water is 1 gram/cm³. Calculate the pressure due to water column at the depth of 0.53 km. (Assume g = 10 m/s²)

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Final answer:

The pressure due to a water column at the depth of 0.53 km is calculated using the formula P = ρgh, resulting in a pressure of 5300 kPa.

Step-by-step explanation:

The formula to calculate the pressure at a certain depth in a fluid is P = ρgh, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the height of the fluid column. Here, ρ is the density of water (1 g/cm³ or 1000 kg/m³), g is given as 10 m/s², and h is the depth of the water column (0.53 km or 530 m).

First, we convert the density of water into SI units, which is 1 g/cm³ = 1000 kg/m³. Then, we substitute these values into the formula:

P = (1000 kg/m³) × (10 m/s²) × (530 m)

P = 5.3 × 10^6 Pa or 5300 kPa.

Therefore, the pressure due to a water column at the depth of 0.53 km is 5300 kPa.

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