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Find f(g(2)), if f(x) = 6/x+1 and g(x) = (x+3)^2

User LarAng
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Final answer:

To find f(g(2)), compute g(2) as (2+3)^2, which equals 5^2 or 25. Then, plug this value into f(x), giving f(25), which simplifies to 6/25 + 1, resulting in f(g(2)) being equal to 1.24.

Step-by-step explanation:

To find f(g(2)), we first need to determine the value of g(2). Since g(x) = (x+3)^2, let's substitute x with 2:

  • g(2) = (2+3)^2
  • g(2) = 5^2
  • g(2) = 25

Now that we have the value of g(2), we can substitute it into f(x) to find f(g(2)). The function f(x) = 6/x + 1 will be evaluated by replacing x with 25:

  • f(g(2)) = f(25)
  • f(g(2)) = 6/25 + 1
  • f(g(2)) = 0.24 + 1
  • f(g(2)) = 1.24

Therefore, f(g(2)) is equal to 1.24.

User RejeeshChandran
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