The equation of line n, which is parallel to line k and passes through the point (2, -4), is y = 2x - 8.
The equation of line k is y = 2x + 1. Given that line n is parallel to line k and passes through the point (2, -4), we can determine the equation of line n by using the same slope as line k. The slope of line k is 2, so the equation of line n is y = 2x + b, where b is the y-intercept. To find the value of b, we substitute the coordinates of the point (2, -4) into the equation:
-4 = 2(2) + b
-4 = 4 + b
b = -8
Therefore, the equation of line n is y = 2x - 8.
The question probably maybe:
The equation of line k is y=2x 1. Line n is parallel to link k and passes through the point (2,-4)
What equation determines this?