Question

The domain of ƒ(x) is {–1, 0, 2}. If f(x) = 3x + 2, what is the range?

Answer 1

The range of the function ƒ(x) = 3x + 2 with a domain of {-1, 0, 2} is {-1, 2, 8}.

Step-by-step explanation:

The range of a function is the set of all possible output values.

In this case, the function ƒ(x) = 3x + 2 is a linear function with a domain of {-1, 0, 2}.

To find the range, we substitute each value in the domain into the function and calculate the corresponding output.

1. When x = -1, ƒ(x) = 3(-1) + 2 = -1. So, the range includes -1.
2. When x = 0, ƒ(x) = 3(0) + 2 = 2. So, the range includes 2.
3. When x = 2, ƒ(x) = 3(2) + 2 = 8. So, the range includes 8.

Therefore, the range of the function ƒ(x) = 3x + 2 is {-1, 2, 8}.