Question

A 50.00-mL sample of aqueous Ca(OH)2 requires 34.66 mL of 0.832 M nitric acid for neutralization. Calculate the concentration (molarity) of the original solution of calcium hydroxide.

Answer 1

The concentration (molarity) of the original solution of calcium hydroxide is 0.0244 M.

Step-by-step explanation:

To calculate the concentration (molarity) of the original solution of calcium hydroxide, we can use the balanced chemical equation for the neutralization reaction:

Ca(OH)2(aq) + 2HCl(aq) → CaCl2(aq) + 2H2O(l)

From the given information, we know that 36.6 mL of 0.05 M HCl is required to neutralize 75.00 mL of the saturated Ca(OH)2 solution.

Therefore, we can use the equation:

Mol HCl = Mol Ca(OH)2

(0.05 M)(0.0366 L) = (molarity of Ca(OH)2)(0.075 L)

Solving for the molarity of Ca(OH)2:

Molarity of Ca(OH)2 = (0.0366 L)(0.05 M) / (0.075 L)

= 0.0244 M