Final answer:
To find the number of unique project combinations possible for the 40 students in the elementary statistics class, we can use the concept of permutations. Plugging the values into the formula, we get P(40, 2) = 1560, which is not listed.
Step-by-step explanation:
To find the number of unique project combinations possible, we need to consider that each of the 40 students has a choice between Probability and Descriptive Statistics.
Since there are only two options (Probability and Descriptive Statistics) for each student, we can use the concept of permutations to find the total number of unique project combinations. The formula for permutations is P(n, r) = n! / (n - r)! where n is the total number of options and r is the number of options to be chosen.
In this case, we have 40 students and 2 options. Plugging the values into the formula, we get
P(40, 2) = 40! / (40 - 2)! = 40! / 38! = 40 * 39 = 1560.
Therefore, there are 1560 unique project combinations possible for the 40 students in the elementary statistics class.