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What is the strength of the electric field at the position (x,y)=(0cm,5.0cm) ?

User Boba Fit
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Final answer:

The electric field strength at a certain point due to a point charge can be calculated using Coulomb's law, with the formula E = k * |q| / r², where k is Coulomb's constant, |q| is the magnitude of the charge, and r is the distance from the charge to the point.

Step-by-step explanation:

The strength of the electric field at a point due to a point charge can be calculated using Coulomb's law. Specifically, the electric field (E) due to point charge (q) at a distance (r) is given by the formula:
E = k * |q| / r²

where k is Coulomb's constant (8.99×10¹ N m²/C²), |q| is the magnitude of the charge, and r is the distance from the charge to the point of interest. For this problem, if |q| is known, and the distance r is 5.0 cm (0.05 m), then we can calculate the electric field strength at (0 cm, 5.0 cm) by plugging the values into the formula:

E = (8.99×10¹ N m²/C²) * |q| / (0.05 m)².

It is important to note that the strength is positive, indicating the direction of the electric field is away from the charge if the charge is positive.

User Lorell
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