Final answer:
The sum of three consecutive even integers can be expressed as y + (y-2) + (y-4), where y is the largest number.
Step-by-step explanation:
The sum of three consecutive even integers can be expressed as y + (y-2) + (y-4). This is because consecutive even integers have a difference of 2 between them. So, if the largest number is y, the next even integer would be y-2 and the one before that would be y-4. By adding these three numbers together, we get the sum of the three consecutive even integers.The sum of three consecutive even integers where the largest number is y can be expressed as y + (y-2) + (y-4). This represents the sum of the largest integer y, the next smaller even integer (y-2), and the even integer just before that one (y-4).
Step-by-step explanation:
The largest given even integer is y.
The immediate previous even integer would be 2 less than y, so (y-2).
The one before that would be another 2 less, so (y-4).
The sum is therefore y + (y-2) + (y-4).