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The sum of three consecutive even integers, if the largest number is y, can be expressed as _______.

a) y + (y-2) + (y-4)
b) y + (y+2) + (y+4)
c) y + (y-1) + (y+1)
d) y + (y-3) + (y+3)

User Carleson
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Final answer:

The sum of three consecutive even integers can be expressed as y + (y-2) + (y-4), where y is the largest number.

Step-by-step explanation:

The sum of three consecutive even integers can be expressed as y + (y-2) + (y-4). This is because consecutive even integers have a difference of 2 between them. So, if the largest number is y, the next even integer would be y-2 and the one before that would be y-4. By adding these three numbers together, we get the sum of the three consecutive even integers.The sum of three consecutive even integers where the largest number is y can be expressed as y + (y-2) + (y-4). This represents the sum of the largest integer y, the next smaller even integer (y-2), and the even integer just before that one (y-4).

Step-by-step explanation:

The largest given even integer is y.

The immediate previous even integer would be 2 less than y, so (y-2).

The one before that would be another 2 less, so (y-4).

The sum is therefore y + (y-2) + (y-4).

User Daviewales
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