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With a BAC of 0.10%, you are _________ times more likely to cause a car crash than if you were sober.

1 Answer

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Final answer:

At a BAC of 0.10%, a person's likelihood of causing a car crash is significantly increased compared to being sober, though this answer does not specify an exact multiple. The legal intoxication level is usually between 0.025-0.080% BAC, indicating 0.10% is well above the legal limit to operate a vehicle.

Step-by-step explanation:

With a BAC of 0.10%, you are significantly more likely to cause a car crash compared to if you were sober. However, the exact number of times more likely is not provided in the provided information or in typical statistics. It is well-documented that the risk increases substantially with higher levels of BAC.

For the accurate multiple, one would need to refer to statistical data from studies or organizations that investigate the correlation between BAC levels and the likelihood of traffic accidents.

Legally, alcohol intoxication is commonly defined as a BAC greater than 0.025-0.080%. At 0.10% BAC, a person is already above the legal limit for driving in almost all US states, which is set at 0.08%. Driving at this level of intoxication can lead to significantly impaired motor skills, reaction times, and decision-making abilities, considerably increasing the chances of being involved in a crash.

For example, imagine you are driving and suddenly a pedestrian steps into the road. A sober driver may be able to react quickly and brake in time, but a driver with a BAC of 0.10% may not be able to react in time to avoid hitting the pedestrian.

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