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A horizontal force of 5.0 N pushes a 0.5kg:

a) Determine the acceleration of the object
b) Calculate the work done by the force
c) Find the net force acting on the object
d) Measure the displacement of the object

User Msb
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1 Answer

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Final answer:

The acceleration of the object is 10 m/s². The net force on the object is 5.0 N. Without additional information, we cannot calculate the work done or the displacement of the object.

Step-by-step explanation:

A horizontal force of 5.0 N is applied to a 0.5 kg object. To solve this problem, we will use Newton's second law of motion and the work-energy principle.

a) Determine the acceleration of the object

Acceleration (a) of an object is given by Newton's second law, which states that force (F) equals mass (m) times acceleration (a):
F = ma. Therefore, a = F/m. Plugging in the values: a = 5.0 N / 0.5 kg, which calculates to 10 m/s².

b) Calculate the work done by the force

The work done by a force is calculated as the product of the force and the displacement in the direction of the force: W = F × distance. However, as we do not have the displacement, we cannot calculate work without it.

c) Find the net force acting on the object

If we ignore any other forces acting on the object, such as friction or air resistance, then the net force acting on the object equals the applied force, which in this case is 5.0 N.

d) Measure the displacement of the object

Without additional information about the duration for which the force is applied or the conditions like friction or possible obstacles, the displacement of the object cannot be measured.

User Kalle Richter
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