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Find the differential of y = tan(3t).

a) sec²(3t)
b) 3sec²(3t)
c) sec²(t)
d) 3sec²(t)

User Aerioeus
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2 Answers

3 votes

Final Answer:

The final answer, 3sec²(3t), results from applying the chain rule to differentiate tan(3t), yielding sec²(3t) and multiplying by the derivative of the inner function, which is 3.Therefore the correct option is b.

Step-by-step explanation:

The derivative of y = tan(3t) involves applying the chain rule. To find dy/dt, start by differentiating the outer function, tan(3t), and then multiply by the derivative of the inner function, which is 3t. The derivative of tan(u) is sec²(u), so when the chain rule is applied, dy/dt = sec²(3t) d(3t)/dt. The derivative of 3t with respect to t is simply 3. Therefore, dy/dt = 3 sec²(3t).

When differentiating a trigonometric function like tan(3t), the chain rule becomes crucial. The derivative of tan(u) is sec²(u). Hence, for y = tan(3t), the derivative dy/dt requires applying the derivative of tan(3t) first, resulting in sec²(3t). Then, considering the derivative of the inner function (3t), which is 3, this value is multiplied to the previously obtained derivative of the outer function. Consequently, dy/dt = 3 sec²(3t), indicating that the rate of change of y with respect to t is three times sec²(3t).

In essence, the differentiation of y = tan(3t) incorporates the chain rule, wherein the derivative of the outer function (tan) yields sec²(3t), and the derivative of the inner function (3t) with respect to t results in 3. These derivatives, when combined using the chain rule, produce the final derivative dy/dt = 3 * sec²(3t), demonstrating the rate of change of y concerning t.Thus the correct option is b.

User Juhovh
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8.5k points
0 votes

Final answer:

The differential of y = tan(3t) is found by applying the chain rule of differentiation, which yields the answer as 3sec²(3t). So, the correct answer is b) 3sec²(3t).

Step-by-step explanation:

To find the differential of y = tan(3t), we need to apply the chain rule of differentiation. The derivative of tan(u) with respect to u is sec^2(u). If we let u = 3t, then du/dt = 3, and the derivative of y with respect to t is du/dt multiplied by the derivative of tan(u) with respect to u.

Therefore, the derivative of y with respect to t is 3 multiplied by sec^2(3t), which is option (b) 3sec^2(3t).

User Asia
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