Final answer:
The empirical formula of at least four binary ionic compounds that could be formed.
a) NaCl, K₂O, MgS, AlF₃ = NaCl
b) Li₂O, CaBr₂, BaI₂, SrCl₂ = Li₂O
c) KCl, Na₂O, MgF₂, Al₂S₃ = KCl
d) CsF, Rb₂O, CaS, SrCl₂ = CSF.
Step-by-step explanation:
The empirical formula of an ionic compound can be determined by balancing the charges of the ions that make up the compound. In a binary ionic compound, there are only two types of ions: a cation (positive ion) and an anion (negative ion). The empirical formula is the simplest ratio of the cation and anion in the compound.
Let's analyze each set of compounds to determine the empirical formula:
- a) NaCl: The cation is Na+ and the anion is Cl₋. The charges are balanced and the simplest ratio is 1:1, so the empirical formula is NaCl.
- b) Li₂O: The cation is Li+ and the anion is O₂⁻. The charges are balanced and the simplest ratio is 2:1, so the empirical formula is Li₂O.
- c) KCl: The cation is K⁺ and the anion is Cl⁻. The charges are balanced and the simplest ratio is 1:1, so the empirical formula is KCl.
- d) CsF: The cation is Cs⁺ and the anion is F⁻. The charges are balanced and the simplest ratio is 1:1, so the empirical formula is CsF.