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A boy on his bicycle has a velocity of 12 m/s as he approaches a hill. After 15 seconds he gets to the top and has a velocity of 8 m/s?

User Tomas M
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Final answer:

The acceleration of the boy on the bicycle, as he goes up the hill, can be calculated using the change in velocity and time, resulting in an acceleration of -0.267 m/s², which indicates deceleration.

Step-by-step explanation:

The student's question involves calculating the acceleration of a boy on a bicycle as he ascends a hill. Given that the boy's initial velocity is 12 m/s and his velocity at the top of the hill is 8 m/s over a time span of 15 seconds, we can find the acceleration using the formula a = (v_f - v_i) / t, where a is acceleration, v_f is the final velocity, and v_i is the initial velocity.

To solve for acceleration: a = (8 m/s - 12 m/s) / 15 s = -4 m/s² / 15 s = -0.267 m/s². The negative sign indicates that the bicycle is decelerating as it goes up the hill (i.e., a reduction in speed).

User Doug Watkins
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