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Find the sum of the first 34 terms of the arithmetic sequence. 2, 6, 10, 14...

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Final answer:

To find the sum of the first 34 terms of an arithmetic sequence, you can use the formula: Sum = (n/2)(2a + (n-1)d). In this case, the first term is 2 and the common difference is 4. Substituting these values into the formula gives a sum of 2312.

Step-by-step explanation:

To find the sum of the first 34 terms of an arithmetic sequence, you can use the formula:

Sum = (n/2)(2a + (n-1)d)

Where n is the number of terms, a is the first term, and d is the common difference.

In this case, the first term is 2 and the common difference is 4.

Substituting these values into the formula gives:

Sum = (34/2)(2(2) + (34-1)(4))

Simplifying this, we get:

Sum = 17(4 + 33(4))

Sum = 17(4 + 132)

Sum = 17(136)

Sum = 2312

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