Final answer:
Lead (II) nitrate reacts with potassium iodide in aqueous solution to form a yellow precipitate of lead iodide and a solution of potassium nitrate, following the solubility rules.
Step-by-step explanation:
The statement is true: when a lead (II) nitrate solution reacts with a potassium iodide solution, a chemical reaction occurs. This reaction is a precipitation reaction where the ions in the reactant compounds exchange partners, forming new compounds. According to the solubility rules, lead iodide is an insoluble compound that will form a precipitate, while potassium nitrate remains soluble in solution.
The balanced chemical equation for this reaction is: 2KI(aq) + Pb(NO3)2(aq) → PbI2(s) + 2KNO3(aq). This demonstrates the formation of a yellow solid precipitate of lead iodide (PbI2), which is evidence of the chemical reaction.