Question

Arrange the following bonds by increasing bond polarity.

a) C-H
b) O-H
c) N-H
d) F-H

Answer 1

To arrange the bonds C-H, O-H, N-H, F-H by increasing bond polarity, we look at the electronegativity difference between the atoms. The arranged order from least to most polar is: C-H, N-H, O-H, F-H, with F-H being the most polar due to fluorine's high electronegativity.

Step-by-step explanation:

To arrange the following bonds by increasing bond polarity: C-H, O-H, N-H, F-H, we consider the electronegativity (EN) difference between the bonded atoms. The greater the difference in EN, the more polar the bond is. Electronegativity increases across a period from left to right in the periodic table and decreases down a group.

1. C-H: Carbon and hydrogen have a small EN difference, making this bond the least polar.
2. N-H: Nitrogen is more electronegative than carbon, so the N-H bond is more polar than C-H but less polar than O-H and F-H.
3. O-H: Oxygen is more electronegative than nitrogen, hence the O-H bond is more polar than N-H but less polar than F-H.
4. F-H: Fluorine is the most electronegative element, making the F-H bond the most polar of all listed.

The arranged order from least to most polar is C-H, N-H, O-H, F-H.