Question

If an object is instead dropped from height 2h, in terms of t, the relationship between the time of fall (t) and the initial height (2h) can be expressed as:

a) t = √(2h/g)
b) t = 2√(h/g)
c) t = √(h/g)
d) t = h/g

Answer 1

The correct equation representing the relationship between the time of fall (t) and initial height (2h) is t = √(2h/g), which is derived from the kinematic equation h = ½ gt².

Step-by-step explanation:

The relationship between the time of fall (t) and the initial height (2h) when an object is dropped from height 2h can be determined using the kinematic equation for free-fall motion, which is h = ½ g t². When solving for t as a function of height, we need to rearrange this formula to express t in terms of h. In this case, for a doubled height 2h, we isolate t to get t = √(2h/g). Therefore, the correct answer is a) t = √(2h/g).