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A student combined 3.88 grams of Iron metal with 250.0 mL of 0.350 M of cooper (II) nitrate and observed the reaction to take place. The products that run through a filtration apparatus and the solid that was produced had an actual mass of 4.11 grams. Irons charge is +3. What is the theoretical yield in grams of the solid product? Show ALL work.

User Asutosh
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Final answer:

To calculate the theoretical yield of the solid product, divide the mass of Iron by its molar mass to get moles of Iron. Then use the stoichiometry of the balanced chemical equation to find the moles of the solid product. Theoretical yield of the solid product is 4.11 grams.

Step-by-step explanation:

The theoretical yield in grams of the solid product can be calculated using the given information. First, convert the mass of Iron metal to moles by dividing it by the molar mass of Iron (55.85 g/mol). Then, use the stoichiometric mole ratio from the balanced chemical equation to determine the number of moles of the solid product produced. Finally, multiply the number of moles by the molar mass of the solid product to obtain the theoretical yield in grams.

Given:

Mass of Iron metal (Fe) = 3.88 grams

Molar mass of Iron (Fe) = 55.85 g/mol

Moles of Iron = Mass of Iron metal / Molar mass of Iron

= 3.88 g / 55.85 g/mol

= 0.0695 mol

Stoichiometric ratio of Fe to solid product: 3 Fe: 1 solid product

Moles of solid product = Moles of Iron * (1 mol solid product / 3 mol Fe)

= 0.0695 mol * (1/3)

= 0.0232 mol

Molar mass of solid product = mass of solid product / Moles of solid product

= 4.11 g / 0.0232 mol

= 177.16 g/mol

Theoretical yield of the solid product = Moles of solid product * Molar mass of solid product

= 0.0232 mol * 177.16 g/mol

= 4.11 grams

User StackTrace
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