a) The solution set in interval notation is (-9, 3]) and on a number.
b) The solution set in interval notation is (-∞, 2), (10/3, ∞)
How to determine values of absolute function
Given:
1. |x + 3| - 9 <= -3
Add 9 to both sides:
|x + 3| <= 6
This implies two cases:
x + 3 <=6 → x <= 3
-(x + 3) <=6 → x => -9
The solution set in interval notation is (-9, 3]) and on a number
2. For |3x - 8| - 4 > -2
Add 4 to both sides:
|3x - 8| > 2
This implies two cases:
3x - 8 > 2 → x > 10/3
-(3x - 8) > 2 → x < 2
The solution set in interval notation is (-∞, 2), (10/3, ∞)