Answer:
y = 1.19 m
Step-by-step explanation:
For this exercise, let's use the projectile launch ratios, find the components of the initial velocity
sin 26 = v_{oy} / v₀
cos 26 = v₀ₓ / v₀
v_{oy} = v₀ sin 26
v₀ₓ = v₀ cos 26
v_{oy} = 11.3 sin 26 = 4.95 m / s
v₀ₓ = 11.3 cos 26 = 10.16 m / s
Let's find the time it takes to cross the river
x = v₀ₓ t
t = x / v₀ₓ
t = 6.27 / 10.16
t = 0.617 s
now with that time we can find how high the body is
y = y₀ + v_{oy} t - ½ g t²
let's calculate
y = 0 + 4.95 0.617 - ½ 9.8 0.617²
y = 1,189 m
the result must have three significant figures
y = 1.19 m