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Nour and Leo's teacher gave them a system of linear equations to solve. They each took a few steps that led to the systems shown in the table below. Teacher -4x+10y=8 -5x-11y=7 Nour Leo -9x-y=8 -4x+10y=1 -5x-11y=1 -9x-y=8 Which of them obtained a system that is equivalent to the teacher's system? Remember that two linear systems are "equivalent" if they have the same solution. Choose 1 answer:

User Hendekagon
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(d) None obtained a system that is equivalent to the teacher's system

Which of them obtained a system that is equivalent to the teacher's system?

From the question, we have the following parameters that can be used in our computation:

Teacher

-4x + 10y = 8

-5x - 11y = 7

Nour

-9x - y = 8

-4x + 10y = 1

Leo

-5x - 11y = 1

-9x - y = 8

Add the equations in the Teacher's system

-9x - y = 15

This means that one of the equations in their system must be -9x - y = 15

We can see that none of the equations in the students' system is -9x - y = 15

Hence, none obtained an equivalent system

Question

Nour and Leo's teacher gave them a system of linear equations to solve. They each took a few steps that led to the systems shown in the table below.

Teacher

-4x + 10y = 8

-5x - 11y = 7

Nour

-9x - y = 8

-4x + 10y = 1

Leo

-5x - 11y = 1

-9x - y = 8

Which of them obtained a system that is equivalent to the teacher's system? Remember that two linear systems are "equivalent" if they have the same solution.

Choose 1 answer:

Leo's system

Nour's system

Both systems

None

User Vasil Oreshenski
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8.6k points
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